Question

How do you factor `2x^2+12xy+18y^2`?

Answer 1

the answer is `2(x+3y)^2`

Explanation:

first you find the GCF(greatest common factor) and that will be `2` so you'll get`2(x^2+6xy+9y^2)` and the rest inside is from what you get when you multiply `2` and the rest. now you have to figure out what two numbers that multiply to give you `9` and add to `6` so `3,3` and now you'll get `2(x+3y^2)` i shortened it but you don't have to if you have`x^2`, you don't have to do the long way, you can just figure it out from there. but this one, there's two `3s` so you can just put it like this`2(x+3y^2)`