How do you factor $2x^2+3x-2$ ?

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Answer 1 · 2015-05-22T15:04:44

You can find its roots and then turn them into factors. I"ll use Bhaskara to find the roots.

$(-3+-sqrt(9-4(2)(-2)))/4$
$(-3+-5)/4$
$x_1=-2$ , which is the same as the factor $x+2=0$
$x_2=1/2$ , which is the same as the factor $2x-1=0$

Thus,

$2x^2+3x-2=(x+2)(2x-1)$

Answer 2 · 2015-05-29T09:29:50

$2x^2 + 3x - 2$

Product = - 4
Sum = +3
Factors = 4, - 1
=

So spiting it up

$2x^2 - x + 4x - 2$

$x ( 2x - 1)+2(2x - 1)$
$(x + 2)(2x -1)$
=

Hence factored

How do you factor 2x^2+3x-22x^2+3x-2?