# How do you factor  2x^2+5x=8?

Jun 7, 2018

$x = \frac{- 5 \pm \sqrt{89}}{4}$

#### Explanation:

$2 {x}^{2} + 5 x = 8$

$2 {x}^{2} + 5 x - 8 = 0$

At this point you cannot factor directly or by grouping so you must either complete the square or use the quadratic formula.

$a {x}^{2} + b x + c$

$x = \frac{- b \pm \sqrt{{b}^{2} - 4 a c}}{2 a}$

$x = \frac{- 5 \pm \sqrt{{5}^{2} - 4 \cdot 2 \cdot - 8}}{2 \cdot 2}$

$x = \frac{- 5 \pm \sqrt{89}}{4}$