How do you factor #2x^3 - 4x^2 + x - 2#?
1 Answer
Jan 23, 2016
# (x - 2)(2x^2 + 1 ) #
Explanation:
Factorise by 'grouping'
ie [
#2x^3 - 4x^2 ] + [ x - 2 ]#
# = 2x^2(x - 2 ) +1 (x - 2 ) # There is now a common factor of ( x - 2 )
= (x - 2 )(2
#x^2 + 1 )#