How do you factor #2y^2 +5y -12# by grouping?

1 Answer
Jul 16, 2016

Answer:

(2y - 3)(y + 4)

Explanation:

#f(y) = 2y^2 + 5y - 12#
Factor f(y) by the AC Method.
Find 2 numbers knowing product (ac = -24) and sum (b = 5).
They are: -3 and 8. Replace in the equation 5y by (-3y + 8y)
f(y) = 2y^2 - 3y + 8y - 12
Factor by grouping:
f(y) = y(2y - 3) + 4(2y - 3) = (2y - 3)(y + 4)