How do you factor #32 - 18x^2#?

1 Answer
Oct 1, 2015

Answer:

First separate out the common scalar factor #2#, then use the difference of squares identity to find:

#32 - 18x^2 = 2(4-3x)(4+3x)#

Explanation:

The difference of squares identity is: #a^2 - b^2 = (a-b)(a+b)#

Using #a = 4# and #b = 3x#, we find:

#32 - 18x^2 = 2(16-9x^2) = 2(4^2 - (3x)^2) = 2(4-3x)(4+3x)#