How do you factor $32x^2 – 8$ ?

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Answer 1 · 2015-05-13T07:55:17

$8$ is a common factor to both the terms in the expression:

$32x^2 - 8 = 8(4x^2 - 1)$

$= 8((2x)^2 - 1^2)$

We know that $color(blue)(a^2 - b^2 = (a+b)(a-b)$

Hence the above expression can be written as :

$= color(green)(8(2x+1)(2x-1)$

How do you factor 32x^2 – 832x^2 – 8?