# How do you factor 3bc-2b-10+15c?

Jan 20, 2017

$3 b c - 2 b - 10 + 15 c = \left(b + 5\right) \left(3 c - 2\right)$

#### Explanation:

This quadrinomial factors by grouping (at least once we swap a couple of the terms around)...

$3 b c - 2 b - 10 + 15 c = 3 b c - 2 b + 15 c - 10$

$\textcolor{w h i t e}{3 b c - 2 b - 10 + 15 c} = \left(3 b c - 2 b\right) + \left(15 c - 10\right)$

$\textcolor{w h i t e}{3 b c - 2 b - 10 + 15 c} = b \left(3 c - 2\right) + 5 \left(3 c - 2\right)$

$\textcolor{w h i t e}{3 b c - 2 b - 10 + 15 c} = \left(b + 5\right) \left(3 c - 2\right)$