How do you factor #3bc-2b-10+15c#?

1 Answer
Jan 20, 2017

#3bc-2b-10+15c = (b+5)(3c-2)#

Explanation:

This quadrinomial factors by grouping (at least once we swap a couple of the terms around)...

#3bc-2b-10+15c = 3bc-2b+15c-10#

#color(white)(3bc-2b-10+15c) = (3bc-2b)+(15c-10)#

#color(white)(3bc-2b-10+15c) = b(3c-2)+5(3c-2)#

#color(white)(3bc-2b-10+15c) = (b+5)(3c-2)#