# How do you factor 3d^2+23d+14 completely?

Nov 15, 2016

$d = - \frac{2}{3}$ and $d = - 7$

#### Explanation:

$3 {d}^{2} + 23 d + 14 = 0$

$3 {d}^{2} + 21 d + 2 d + 14 = 0$

$3 d \left(d + 7\right) + 2 \left(d + 7\right) = 0$

$\left(3 d + 2\right) \left(d + 7\right) = 0$

$3 d + 2 = 0$ and $d + 7 = 0$

$d = - \frac{2}{3}$ and $d = - 7$