Question

How do you factor #3v^3 + 4v - 2v^2 #?

Answer 1

`=v(3v^2+4-2v)`

Explanation:

`3v^3-4v -2v^2`

The only factor that all the terms have in common is `v`

Divide `v` from each term

`=v(3v^2+4-2v)`

There are now two factors.