How do you factor 3x^2 - 27(2-x)^2? Algebra Polynomials and Factoring Factoring Completely 1 Answer Deepak G. Aug 7, 2016 =-12(x-3)(2x-3) Explanation: 3x^2-27(2-x)^2 =3x^2-27(4+x^2-4x) =3x^2-27(4)-27x^2+27(4x) =3x^2-108-27x^2+108x =-24x^2+108x-108 =-12(2x^2-9x+9) =-12(2x^2-6x-3x+9) =-12(2x(x-3)-3(x-3)) =-12(x-3)(2x-3) Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely 2x^2-8? Which method do you use to factor 3x(x-1)+4(x-1) ? What are the factors of 12x^3+12x^2+3x? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor 12c^2-75 completely? How do you factor x^6-26x^3-27? How do you factor 100x^2+180x+81? See all questions in Factoring Completely Impact of this question 5779 views around the world You can reuse this answer Creative Commons License