How do you factor #3x^2 + 7x + 2#?

1 Answer
Mar 25, 2016

Answer:

(3x + 1)(x + 2)

Explanation:

Use the new AC Method to factor trinomials (Socratic Search)
#y = 3x^2 + 7x + 2 =# 3(x = p)(x + q)
Converted trinomial #y' = x^2 + 7x + 6 = #(x + p')(x + q')
Factor pair of (6) --> (1, 6). This sum is 7 = b. Then p' = 1 and q' = 6. Back to y, #p = 1/3# and #q = 6/3 = 2.#
#y = 3(x + 1/3)(x + 2) = (3x + 1)(x + 2)#