How do you factor $3 x^{5} y^{2} - 21 x^{2} y^{7}$ $3x^5y^2-21x^2y^7$ ?

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Answer 1 · 2018-03-17T21:52:45

$3 x^{2} y^{2} (x^{3} - 7 y^{5})$ $3x^2y^2(x^3-7y^5)$

$3 x^{5} y^{2} - 21 x^{2} y^{7} = 3 x^{2} y^{2} (x^{3} - 7 y^{5})$ $3x^5y^2−21x^2y^7=3x^2y^2(x^3-7y^5)$

How do you factor 3x5y2−21x2y73x^5y^2-21x^2y^7?