# How do you factor: #3y - 6x + 4xy - 2y^2#?

##### 1 Answer

Aug 29, 2016

#### Answer:

#### Explanation:

Group the terms in 'pairs'

That is

#[3y-6x]+[4xy-2y^2]# now factorise each 'pair' by taking out a

#color(blue)"common factor"#

#rArrcolor(red)(3)(y-2x)color(red)(-2y)(y-2x)# We now have a

#color(blue)"common factor"# of (y - 2x)

#rArr(y-2x)(color(red)(3-2y))#

#rArr3y-6x+4xy-2y^2=(y-2x)(3-2y)#