How do you factor #48x^2y + 20xz +12xy + 5z#?

1 Answer
Alan P.
Apr 9, 2015

Examine the expression #48x^2y+20xz+12xy+5z# for pairs of terms with common factors, then group those terms and extract the common factors:
#(48x^2y+12xy) + (20xz+5z)#

#(12xy)(4x+1) + (5z)(4x+1)#

Note and separate out the common factor from each term:
#(4x+1)(12xy+5z)#

Related questions
See all questions in Factoring by Grouping
Impact of this question
1903 views around the world
You can reuse this answer
Creative Commons License