# How do you factor 48y^2 - 72xy + 27x^2?

The answer is $3 {\left(3 x - 4 y\right)}^{2}$
In the given expression we can see that the coefficients of the polynomials are $48 , 72$ and $27$ these numbers are divisible by $3$
$3 \left(9 {x}^{2} - 24 x y + 16 {y}^{2}\right)$
and when we factorise $9 {x}^{2} - 24 x y + 16 {y}^{2}$ we get ${\left(3 x - 4 y\right)}^{2}$
so finally we get $3 {\left(3 x - 4 y\right)}^{2}$ as our answer.