Question

How do you factor `48y^2 - 72xy + 27x^2`?

Answer 1

The answer is `3(3x-4y)^2`

Explanation:

In the given expression we can see that the coefficients of the polynomials are `48,72` and `27` these numbers are divisible by `3`
When you take 3 common from these numbers this expression becomes:
`3(9x^2-24xy+16y^2)`
and when we factorise `9x^2-24xy+16y^2` we get `(3x-4y)^2`
so finally we get `3(3x-4y)^2` as our answer.