How do you factor #4a^2-28a+48#? Algebra Polynomials and Factoring Factoring Completely 1 Answer Hubert May 22, 2015 #4a^2-28a+48=4(a-3)(a-4)# It's a quadratic so: #Delta=(-28)^2-4*4*48=16# #sqrt(Delta)=4# #a_1=(-(-28)-4)/(2*4)=24/8=3# #a_2=(-(-28)+4)/(2*4)=32/8=4# Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 1843 views around the world You can reuse this answer Creative Commons License