How do you factor 4a^2-28a+48? Algebra Polynomials and Factoring Factoring Completely 1 Answer Hubert May 22, 2015 4a^2-28a+48=4(a-3)(a-4) It's a quadratic so: Delta=(-28)^2-4*4*48=16 sqrt(Delta)=4 a_1=(-(-28)-4)/(2*4)=24/8=3 a_2=(-(-28)+4)/(2*4)=32/8=4 Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely 2x^2-8? Which method do you use to factor 3x(x-1)+4(x-1) ? What are the factors of 12x^3+12x^2+3x? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor 12c^2-75 completely? How do you factor x^6-26x^3-27? How do you factor 100x^2+180x+81? See all questions in Factoring Completely Impact of this question 1943 views around the world You can reuse this answer Creative Commons License