How do you factor $4 a^{2} - 5 a b$ $4a^2 - 5ab$ ?

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How do you factor $4 a^{2} - 5 a b$ $4a^2 - 5ab$ ?

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Answer 1 · 2017-10-02T17:39:43

$a (4 a - 5 b)$ $a(4a-5b)$

Explanation:

To factor a number or expression means to write it as the product of its prime factors.

In Algebra, always check for a common factor first.

$4 a^{2} - 5 a b \leftarrow H C F = a$ $4a^2-5ab" "larr HCF = a$

Divide $a$ $a$ out of each term:

$= a (4 a - 5 b) \leftarrow$ $= a(4a-5b)" "larr$ there are now 2 factors

Answer 2 · 2017-10-02T17:40:24

$a (4 a - 5 b)$ $a(4a-5b)$

Explanation:

$there is a common factor of a in both terms$ $"there is a "color(blue)"common factor ""of a in both terms"$
$which can be taken out$ $"which can be taken out"$

$\Rightarrow 4 a^{2} - 5 a b = a (4 a - 5 b) \leftarrow factored form$ $rArr4a^2-5ab=a(4a-5b)larr" factored form"$

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How do you factor $4 a^{2} - 5 a b$ $4a^2 - 5ab$ ?

2 Answers

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How do you factor $4 a^{2} - 5 a b$ $4a^2 - 5ab$ ?