How do you factor $4 g^{2} - 40 g + 36$ $4g ^ { 2} - 40g + 36$ ?

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How do you factor $4 g^{2} - 40 g + 36$ $4g ^ { 2} - 40g + 36$ ?

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Answer 1 · 2017-03-22T03:59:09

$(4 g - 36) (g - 1)$ $(4g-36) (g-1)$

Explanation:

Find factors of $4$ $4$ that when cross multiplied to the factors of $36$ $36$ will equal to $- 40$ $-40$ .

For example,

$4 - 36$ $4" " -36$

$1 - 1$ $1" " -1$

When you cross multiply $- 1$ $-1$ and $4$ $4$ to get $- 4$ $-4$ . Then cross multiply $1$ $1$ and $- 36$ $-36$ to get $- 36$ $-36$ . Once you add them, you get $- 40$ $-40$ .

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How do you factor $4 g^{2} - 40 g + 36$ $4g ^ { 2} - 40g + 36$ ?

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How do you factor $4 g^{2} - 40 g + 36$ $4g ^ { 2} - 40g + 36$ ?