How do you factor #4s^2-26st+81t^2# using the perfect squares formula?

Question

1534 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-06-17T04:50:07

#y = 4s^2 - 26st + 81t^2 #
To be considered as a perfect square, y must be:
#y = 4s^2 - 36st + 81t^2 = (2s + 9t)^2#.
There might be a typing error?