How do you factor #4x^2-152x+690=0#?

1 Answer

Answer:

Refer to explanation

Explanation:

Hence it is trinomial we find its roots as follows

#x_(1,2)=(-b^2+-sqrt(b^2-4ac))/(2a)#

where #a=4 , b=-152 , c=690# hence we have that

#x_1=1/2*(38-sqrt(754))# and #x_2=1/2*(38+sqrt(754))#

Hence it can be factor as follows

#4x^2-152x+690=(x-x_1)*(x-x_2)#