How do you factor $54r^3 - 45r^2 + 9r$ ?

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Answer 1 · 2015-07-02T00:15:20

Factor: $f(r) = 54r^3 - 45r^2 + 9r$

$f(r) = 7r(6r^2 - 5r + 1)$

Factor the trinomial in parentheses:

$(6r^2 - 3r - 2r + 1) = 3r(2r - 1) - (2r + 1) = (2r -1)(3r - 1)$

$f(r) = 7r(2r - 1)(3r - 1)$

How do you factor 54r^3 - 45r^2 + 9r54r^3 - 45r^2 + 9r?