# How do you factor 54x^4-2xy^6?

$2 x \left(3 x - {y}^{2}\right) \left(9 {x}^{2} + 3 x {y}^{2} + {y}^{4}\right)$
$54 {x}^{4} - 2 x {y}^{6} = 2 x \left(27 {x}^{3} - {y}^{6}\right)$
$= 2 x \left({\left(3 x\right)}^{3} - {\left({y}^{2}\right)}^{3}\right) = 2 x \left(3 x - {y}^{2}\right) \left(9 {x}^{2} + 3 x {y}^{2} + {y}^{4}\right)$