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How do you factor $54x^4-2xy^6$ ?

1 Answer

Oct 27, 2015

$2x(3x-y^2)(9x^2+3xy^2+y^4)$

Explanation:

$54x^4-2xy^6= 2x(27x^3-y^6)$
$=2x((3x)^3-(y^2)^3)= 2x(3x-y^2)(9x^2+3xy^2+y^4)$

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