How do you factor #5n^2-4n-1#?
(5n + 1)(n - 1)
Use the new AC Method (Socratic, Google Search)
Method. Find the 2 factor numbers of y', then, divide them by a.
Find 2 numbers, that have opposite signs (ac < 0), knowing their sum (b = -4) and their product (ac = - 5). They are 1 and - 5.
Back to y, the factor-numbers are: