How do you factor #5x^3+4x^2-10x-8 # by grouping? Algebra Polynomials and Factoring Factoring by Grouping 1 Answer Ratnaker Mehta Sep 7, 2016 #(x^2-2)(5x+4)# Explanation: Let #p(x)=5x^3+4x^2-10x-8# #=ul(5x^3-10x)+ul(4x^2-8)# #=5x(x^2-2)+4(x^2-2)# #=(x^2-2)(5x+4)# Answer link Related questions What is Factoring by Grouping? How do you factor by grouping four-term polynomials and trinomials? Why does factoring polynomials by grouping work? How do you factor #2x+2y+ax+ay#? How do you factor #3x^2+8x+4# by using the grouping method? How do you factor #6x^2-9x+10x-15#? How do you group and factor #4jk-8j^2+5k-10j#? What are the factors of #2m^3+3m^2+4m+6#? How do you factor quadratics by using the grouping method? How do you factor #x^4-2x^3+5x-10#? See all questions in Factoring by Grouping Impact of this question 2810 views around the world You can reuse this answer Creative Commons License