# How do you factor 6-2(n+4)?

Oct 8, 2016

$- 2 \left(n + 1\right)$

#### Explanation:

Distribute the $- 2$ throughout the set of parenthesis
$6 - 2 n - 8$

Combine like terms
$6 - 8 = - 2$

So the problem now looks like:
$- 2 n - 2$

To factor, you would take out a GCF (Greatest Common Factor)
$- 2 \left(n + 1\right)$