# How do you factor -62x^5 y^2 + 124x^4 y^3?

$- 62 {x}^{5} {y}^{2} + 124 {x}^{4} {y}^{3} = 62 {x}^{4} {y}^{2} \left(2 y - x\right)$
Both terms are divisible by $62$, ${x}^{4}$ and ${y}^{2}$, so divisible by $62 {x}^{4} {y}^{2}$:
$- 62 {x}^{5} {y}^{2} + 124 {x}^{4} {y}^{3} = 62 {x}^{4} {y}^{2} \left(- x + 2 y\right) = 62 {x}^{4} {y}^{2} \left(2 y - x\right)$