How do you factor $- 62 x^{5} y^{2} + 124 x^{4} y^{3}$ $-62x^5 y^2 + 124x^4 y^3$ ?

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Answer 1 · 2016-05-09T19:33:46

$- 62 x^{5} y^{2} + 124 x^{4} y^{3} = 62 x^{4} y^{2} (2 y - x)$ $-62x^5y^2+124x^4y^3 = 62x^4y^2(2y-x)$

Both terms are divisible by $62$ $62$ , $x^{4}$ $x^4$ and $y^{2}$ $y^2$ , so divisible by $62 x^{4} y^{2}$ $62x^4y^2$ :

$- 62 x^{5} y^{2} + 124 x^{4} y^{3} = 62 x^{4} y^{2} (- x + 2 y) = 62 x^{4} y^{2} (2 y - x)$ $-62x^5y^2+124x^4y^3=62x^4y^2(-x+2y) = 62x^4y^2(2y-x)$

How do you factor −62x5y2+124x4y3-62x^5 y^2 + 124x^4 y^3?