How do you factor #6a^3+ 8a^2+ 2a#?
1 Answer
May 25, 2018
Explanation:
#"take out a "color(blue)"common factor "2a#
#=2a(3a^2+4a+1)#
#"factor the quadratic using the a-c method"#
#"the factors of the product "3xx1=3#
#"which sum to + 4 are + 3 and + 1"#
#"split the middle term using these factors"#
#3a^2+3a+a+1larrcolor(blue)"factor by grouping"#
#=color(red)(3a)(a+1)color(red)(+1)(a+1)#
#"take out the "color(blue)"common factor "(a+1)#
#=(a+1)(color(red)(3a+1))#
#6a^3+8a^2+2a=2a(a+1)(3a+1)#
