How do you factor $6r^3m^3-42r^2m^2+54rm-378$ ?

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Answer 1 · 2015-07-08T07:10:45

Factor out the GCF $6$ . Then factor by grouping.

$6r^3m^3-42r^2m^2+54rm-378$

Factor out the GCF $6$ .

$6(r^3m^3-7r^2m^2+9rm-63)$

Factor by grouping.

$6(r^3m^3-7r^2m^2)+(9rm-63)$

Factor out common terms for both groups.

$6(r^2m^2(rm-7))+(9(rm-7))$

Factor out the common term $(rm-7)$ .

$6(r^2m^2+9)(rm-7)$

How do you factor 6r^3m^3-42r^2m^2+54rm-3786r^3m^3-42r^2m^2+54rm-378?