How do you factor # 6x^2 - 11x + 2 = 0#?

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Answer 1 · 2017-07-18T15:06:06

#y = 6x^2 - 11x + 2 = 0#
#D = b^2 - 4ac = 121 - 48 = 73#
Since D isn't a perfect square, this trinomial can't be factored.