How do you factor 6x^2-5x+1?

Jul 16, 2015

Factor $y = 6 {x}^{2} - 5 x + 1$
y = (3x - 1)(2x - 1)

Explanation:

Use the new AC Method
Converted $y ' = {x}^{2} - 5 x + 6.$
Factor pairs of ac = 6 -> (1, 6)(2, 3) -> This sum is 5 = -b.
p' = -2 and q' = -3
$p = - \frac{2}{6} = - \frac{1}{3}$ and $q = - \frac{3}{6} = - \frac{1}{2}$

Factor form y = 6(x - 1/3)(x - 1/2) = (3x - 1)(2x - 1)