# How do you factor  8(1+y)+2y(1+y)?

$2 \left(4 \left(1 + y\right) + y \left(1 + y\right)\right)$
In this case, the terms we have are $8 \left(1 + y\right)$ and $2 y \left(1 + y\right)$. They can both be rewritten as $2 \left(4 \left(1 + y\right)\right)$ and $2 \left(y \left(1 + y\right)\right)$. Both of these terms have a common factor of $2$, so we simply take $2$ out of the expression as a factor of both terms.