How do you factor $81z^2 + 36z + 4$ ?

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Answer 1 · 2015-05-20T12:20:55

Problem: Factor $81z^2+36z+4$ .

This is an example of the square of the sum formula:

$(a+b)^2=a^2+2ab+b^2$

$a=9z$
$b=2$

$(9z)^2+2(9z)(2)+2^2$

The factorization of $81z^2+36z+4=(9z+2)^2$ .

How do you factor 81z^2 + 36z + 481z^2 + 36z + 4?