How do you factor #8ac-2ad+4bc-bd#?

1 Answer
EZ as pi
Feb 17, 2017

#(4c-d)(2a+b)#

Explanation:

There are 4 terms and there is no common factor in all of them.
But it is possible to group them into two pairs to make common factors.

#(8ac-2ad) + (4bc-bd)#

#=2acolor(blue)((4c-d))+bcolor(blue)((4c-d))" "# there is a common bracket

#= color(blue)((4c-d))(2a+b)#

There are now two factors.

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