How do you factor #8ac-2ad+4bc-bd#?

1 Answer
EZ as pi
Feb 17, 2017

#(4c-d)(2a+b)#

Explanation:

There are 4 terms and there is no common factor in all of them.
But it is possible to group them into two pairs to make common factors.

#(8ac-2ad) + (4bc-bd)#

#=2acolor(blue)((4c-d))+bcolor(blue)((4c-d))" "# there is a common bracket

#= color(blue)((4c-d))(2a+b)#

There are now two factors.

Related questions
See all questions in Monomial Factors of Polynomials
Impact of this question
3568 views around the world
You can reuse this answer
Creative Commons License