How do you factor  8x^2-18?

Apr 4, 2018

$2 \left(2 x + 3\right) \left(2 x - 3\right)$

Explanation:

First, factor out the GCF (2)

$2 \left(4 {x}^{2} - 9\right) \rightarrow 4 {x}^{2} - 9$ can be factored out using difference of squares:

${a}^{2} - {b}^{2} = \left(a - b\right) \left(a + b\right)$

$a$ in this case is $2 x$, $b$ is $3$

$\left(2 x - 3\right) \left(2 x + 3\right)$

$2 \left(2 x - 3\right) \left(2 x + 3\right)$