How do you factor #8x^2+8x+2#?

1 Answer
Mar 13, 2018

Answer:

#(4x+2)(2x+1)#

Explanation:

#8x^2+8x+2#

Find the product of the coefficient of #x^2# and the constant, or #(a*c)#,.then find two factors such that when you multiply them they will give you #16# and when you add them they will give you #8#.

#8x^2+4x+4x+2#

Factorise

#4x(2x+1)+2(2x+1)#

#(4x+2)(2x+1)#