How do you factor $8x^3 - 27y^3$ ?

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Answer 1 · 2015-06-10T02:01:20

$8x^3 - 27y^3=(2x-3y)(4x^2+6xy+9y^2)$

Use the identity $a^3 - b^3 = (a - b)(a^2 + ab + b^2)$

$a=2x$
$b=3y$

$8x^3 - 27y^3 = (2x - 3y)(4x^2 + 6xy + 9y^2)$

How do you factor 8x^3 - 27y^38x^3 - 27y^3?