How do you factor $9c^2 - 25d^4$ ?

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Answer 1 · 2016-03-30T06:14:29

$9c^2-25d^4=(3c-5d^2)*(3c+5d^2)$

$9c^2-25d^4=(3c)^2-(5d^2)^2$

$3c=a$
$5d^2=b$

$(3c)^2-(5d^2)^2=a^2-b^2$

$a^2-b^2=(a-b)*(a+b)$

$9c^2-25d^4=(3c-5d^2)*(3c+5d^2)$

How do you factor 9c^2 - 25d^49c^2 - 25d^4?