# How do you factor 9t^3+66t^2-48t?

Aug 8, 2017

See a solution process below:

#### Explanation:

First, we can factor a $3 t$ out of each term in the expression giving:

$\left(3 t \cdot 3 {t}^{2}\right) + \left(3 t \cdot 22 t\right) - \left(3 t \cdot 16 t\right) \implies$

$3 t \left(3 {t}^{2} + 22 t - 16 t\right)$

Next, we can factor the quadratic as:

$3 t \left(3 t - 2\right) \left(t + 8\right)$