How do you factor by grouping #11x^2 + 33x - xy - 6y#?

2 Answers
Alan P.
Jun 5, 2015

I do not believe there are any rational factors for #11x^2+33x-xy-6y# (Somebody correct me on this).

Perhaps the #-6y# was meant to be #-3y# (?)

George C.
Jun 5, 2015

It looks to me like a factor of #2# has been accidentally omitted from the #-xy# term in the expression. That seems to me to be more likely than the alternatives.

If I am correct, the question should be:

How do you factor by grouping #11x^2+33x-2xy-6y#?

#11x^2+33x-2xy-6y#

#=(11x^2+33x)-(2xy+6y)#

#=11x(x+3)-2y(x+3)#

#=(11x-2y)(x+3)#

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