How do you factor by grouping 12a^3+20a^2-48a?

This expression, $12 {a}^{3} + 20 {a}^{2} - 48 a$, can be factored fairly simply
$\left(4 a\right) \left(3 {a}^{2} + 5 a - 12\right)$
$\left(4 a\right) \left(3 a - 4\right) \left(a + 3\right)$