How do you factor by grouping #2m^4 + 6 - am^4 - 3a#? Algebra Polynomials and Factoring Factoring by Grouping 1 Answer Alan P. Jul 23, 2015 Answer: Extract factors from #2m^4+6# and #-am^4-3a# leaving a factor common to both; then extract that factor: #color(white)("XXXX")##2m^4+6-am^4-3a = (2-a)(m^4+3)# Explanation: #2m^4+6 - am^4-3a# #color(white)("XXXX")##= (color(red)(2m^4+6)) - (color(blue)(am^4+3a))# #color(white)("XXXX")##=color(red)(2)(m^4+3) - color(blue)a(m^4+3)# #color(white)("XXXX")##= (2-a)(m^4+3)# Related questions What is Factoring by Grouping? How do you factor by grouping four-term polynomials and trinomials? Why does factoring polynomials by grouping work? How do you factor #2x+2y+ax+ay#? How do you factor #3x^2+8x+4# by using the grouping method? How do you factor #6x^2-9x+10x-15#? How do you group and factor #4jk-8j^2+5k-10j#? What are the factors of #2m^3+3m^2+4m+6#? How do you factor quadratics by using the grouping method? How do you factor #x^4-2x^3+5x-10#? See all questions in Factoring by Grouping Impact of this question 309 views around the world You can reuse this answer Creative Commons License