How do you factor by grouping 2m^4 + 6 - am^4 - 3a? Algebra Polynomials and Factoring Factoring by Grouping 1 Answer Alan P. Jul 23, 2015 Extract factors from 2m^4+6 and -am^4-3a leaving a factor common to both; then extract that factor: color(white)("XXXX")2m^4+6-am^4-3a = (2-a)(m^4+3) Explanation: 2m^4+6 - am^4-3a color(white)("XXXX")= (color(red)(2m^4+6)) - (color(blue)(am^4+3a)) color(white)("XXXX")=color(red)(2)(m^4+3) - color(blue)a(m^4+3) color(white)("XXXX")= (2-a)(m^4+3) Answer link Related questions What is Factoring by Grouping? How do you factor by grouping four-term polynomials and trinomials? Why does factoring polynomials by grouping work? How do you factor 2x+2y+ax+ay? How do you factor 3x^2+8x+4 by using the grouping method? How do you factor 6x^2-9x+10x-15? How do you group and factor 4jk-8j^2+5k-10j? What are the factors of 2m^3+3m^2+4m+6? How do you factor quadratics by using the grouping method? How do you factor x^4-2x^3+5x-10? See all questions in Factoring by Grouping Impact of this question 2240 views around the world You can reuse this answer Creative Commons License