# How do you factor by grouping 2v^2 + 11v + 5?

Finding its roots is the way to factoring. The roots of the equation are ${v}_{1} = - 5$ and ${v}_{2} = - \frac{1}{2}$ (which is the same as $2 v = - 1$, just changing the side of $2$.
${v}_{1} + 5 = 0$ and $2 {v}_{2} + 1 = 0$
$\left(v + 5\right) \left(2 v + 1\right)$