# How do you factor by grouping: 2x^2 - 6x + 3x - 9?

Apr 18, 2018

$\left(2 x + 3\right) \left(x - 3\right)$

#### Explanation:

We have four terms; thus, we'll need to make two groups of two terms and factor each group. Group together as follows:

$\left(2 {x}^{2} - 6 x\right) + \left(3 x - 9\right)$

$2 {x}^{2} - 6 x = 2 x \left(x - 3\right)$

$3 x - 9 = 3 \left(x - 3\right)$

We then rewrite as

$2 x \left(x - 3\right) + 3 \left(x - 3\right)$

Factoring out $\left(x - 3\right)$ from this, we get

$\left(2 x + 3\right) \left(x - 3\right)$