How do you factor by grouping: #2x^2 - 6x + 3x - 9#?

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Answer 1 · 2018-04-18T22:58:08

#(2x+3)(x-3)#

We have four terms; thus, we'll need to make two groups of two terms and factor each group. Group together as follows:

#(2x^2-6x)+(3x-9)#

#2x^2-6x=2x(x-3)#

#3x-9=3(x-3)#

We then rewrite as

#2x(x-3)+3(x-3)#

Factoring out #(x-3)# from this, we get

#(2x+3)(x-3)#