How do you factor by grouping #2x^3 + 4x^2 y - 2x^2 - 4xy#?

1 Answer
May 4, 2015

Notice the similarity of the coefficients, 2, 4, -2, -4. It prompts to group the four terms of this expression into two groups:
Group 1: #2x^3+4x^2y#
Group 2: #-2x^2-4xy#

Factor out #2x^2# in the first group, getting
#2x^2(x+2y)#
Factor out #-2x# in the second group, getting
#-2x(x+2y)#

Now you see that #(x+2y)# is a common factor in both groups. Therefore, the original expression can be represented as:
#2x^2(x+2y)-2x(x+2y)=(2x^2-2x)(x+y)=2x(x-1)(x+2y)#