How do you factor by grouping #2xz-3z+8x-12y#?

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Answer 1 · 2015-04-15T01:07:10

#2xz-3z+8x-12y# cannot be factored by grouping.

#(2xz-3z)+(8x-12y)#

#=z(2x-3)+4(2x-3y)# The expressions in parentheses are not the same, so we cannot factor any further.

If we had started with: #2xz-3color(red)(y)z+8x-12y# , the we would get:

#color(white)"sssssssssssssssssssss"# #(2xz-3yz)+(8x-12y)#

#color(white)"ssssssssssssssssss"# #= z(2x-3y)+4(2x-3y)#

#color(white)"ssssssssssssssssss"# #= (z+4)(2x-3y)#