# How do you factor by grouping 3bc-4ad+6ac-2bd ?

$3 b c - 4 a d + 6 a c - 2 b d = \left(b + 2 a\right) \left(3 c - 2 d\right)$
$3 b c - 4 a d + 6 a c - 2 b d = \left(3 b c - 2 b d\right) + \left(6 a c - 4 a d\right)$
$= b \left(3 c - 2 d\right) + 2 a \left(3 c - 2 d\right) = \left(b + 2 a\right) \left(3 c - 2 d\right)$