Question

How do you factor by grouping `3x^4+6x^3-6x-12`?

Answer 1

You can collect `3x` from the first and third term and `6` from the second and fourth to get:
`3x(x^3-2)+6(x^3-2)=` now collect `(x^3-2)` and get:
`=(x^3-2)(3x+6)`