How do you factor by grouping $3 x^{4} + 6 x^{3} - 6 x - 12$ $3x^4+6x^3-6x-12$ ?

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How do you factor by grouping $3 x^{4} + 6 x^{3} - 6 x - 12$ $3x^4+6x^3-6x-12$ ?

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Answer 1 · 2015-05-20T19:30:27

You can collect $3 x$ $3x$ from the first and third term and $6$ $6$ from the second and fourth to get:
$3 x (x^{3} - 2) + 6 (x^{3} - 2) =$ $3x(x^3-2)+6(x^3-2)=$ now collect $(x^{3} - 2)$ $(x^3-2)$ and get:
$= (x^{3} - 2) (3 x + 6)$ $=(x^3-2)(3x+6)$

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How do you factor by grouping $3 x^{4} + 6 x^{3} - 6 x - 12$ $3x^4+6x^3-6x-12$ ?

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How do you factor by grouping 3x^4+6x^3-6x-12 3x4+6x3−6x−12 3x^4+6x^3-6x-12 ?

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How do you factor by grouping $3 x^{4} + 6 x^{3} - 6 x - 12$ $3x^4+6x^3-6x-12$ ?