How do you factor by grouping #4b^2+4bc+c^2-16#?

1 Answer
Jun 23, 2015

Answer:

#(2b+c+4)*(2b+c-4)#

Explanation:

#color(red)(4b^2+4bc+c^2) - color(blue)(16)#
rewrite the frist 3 terms as a square
#color(white)("XXXX")##color(red)((2b+c)^2) - color(blue)(4^2)#
this is the difference of squares with a well-know factoring
#color(white)("XXXX")##(2b+c+4)*(2b+c-4)#