# How do you factor by grouping #4z^2+12z-az-3a#?

##### 1 Answer

Apr 13, 2015

(4z-a)(z+3)

Make groups as (4

4z(z+3) -a(z+3).Since z+3 is common to both the terms now, we can again take out the common factor to become (z+3)(4z-a).